If a polynomial function f(x) has roots 3 and radical 7 what must also be a root of f(x)?
Accepted Solution
A:
Answer:The answer is -β7Step-by-step explanation:β΅ The polynomial has roots 3 and β7β΄ It must have root -β7 the conjugate of β7β΄ The roots of f(x) are 3 , β7 , -β7 Β Β (one rational and two irrational conjugate to each other)